IFG at 1000Mb/s
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IFG at 1000Mb/s

 
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Guest






Posted: Thu Jun 16, 2005 8:20 am    Post subject: IFG at 1000Mb/s Reply with quote

There is a note in section 4.4.2.4 of ieee802.3-2002
saying that
"The spacing between two noncolliding packets, from
the last bit of the FCS field of the first packet to
the first bit of the preamble of the second packet,
can have a minimum value of 64 BT (bit times), as
measured at the GMII receive signals at the DTE.
This InterFrameGap shrinkage may be caused by variable
network delays, added preamble bits, and clock tolerances."

Does that mean that a receiving port must be able to cope
with a minimum IFG of 8 bytes?
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Rich Seifert
Guest





Posted: Thu Jun 16, 2005 4:20 pm    Post subject: Re: IFG at 1000Mb/s Reply with quote

In article <1118897353.029369.127230@g47g2000cwa.googlegroups.com>,
adrian.uliana@gmail.com wrote:

Quote:
There is a note in section 4.4.2.4 of ieee802.3-2002
saying that
"The spacing between two noncolliding packets, from
the last bit of the FCS field of the first packet to
the first bit of the preamble of the second packet,
can have a minimum value of 64 BT (bit times), as
measured at the GMII receive signals at the DTE.
This InterFrameGap shrinkage may be caused by variable
network delays, added preamble bits, and clock tolerances."

Does that mean that a receiving port must be able to cope
with a minimum IFG of 8 bytes?

Strictly speaking, yes. In practice, however, Gigabit Ethernet
connections are always simple point-to-point links between an end
station and a switch/router (or a pair of end stations), and operate in
full-duplex mode. In this configuration, there should not be any IFG
shrinkage. However, it is (at least theoretically) possible to build a
Gigabit Ethernet repeater and operate a link in half-duplex mode, in
which case significant IFG shrinkage could occur. A station in such a
configuration must be able to deal with a shorter IFG than that
generated by the original sending station.


--
Rich Seifert Networks and Communications Consulting
21885 Bear Creek Way
(408) 395-5700 Los Gatos, CA 95033
(408) 228-0803 FAX

Send replies to: usenet at richseifert dot com
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Rich Seifert
Guest





Posted: Fri Jun 17, 2005 12:20 am    Post subject: Re: IFG at 1000Mb/s Reply with quote

In article <1118962852.701781.124150@g43g2000cwa.googlegroups.com>,
adrian.uliana@gmail.com wrote:

Quote:
Does that mean the maximum allowable number of bytes a
device can strip from the IFG at any one time is also 4
bytes?
(Assuming worst case scenario of 100%BW and an IFG of
12).

What do mean by "strip bytes from the IFG"? Any transmitting station
(end station or bridge/switch) must enforce the minimum 96-bit IFG
before all transmitted frames. IFG shrinkage occurs through repeaters; I
have never seen one of those for Gigabit Ethernet.


--
Rich Seifert Networks and Communications Consulting
21885 Bear Creek Way
(408) 395-5700 Los Gatos, CA 95033
(408) 228-0803 FAX

Send replies to: usenet at richseifert dot com
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Guest






Posted: Fri Jun 17, 2005 12:20 am    Post subject: Re: IFG at 1000Mb/s Reply with quote

Thanks Rich, I am evaluating some test equipment and
there is some varition in the minimum IFG. Some use 12,
11 or 8. I also need to know what I can support.

I also have another question on the same issue.
Does that mean the maximum allowable number of bytes a
device can strip from the IFG at any one time is also 4
bytes?
(Assuming worst case scenario of 100%BW and an IFG of
12).
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Guest






Posted: Fri Jun 17, 2005 6:25 am    Post subject: Re: IFG at 1000Mb/s Reply with quote

By strip, I meant shrink.

So, if you had a switch that was only transfering traffic between 2
ports at 100% BW,
wouldn't almost every IFG by 12 but at some point it'd have to shrink
it to 11 to account
for the clock differences on the 2 ports to prevent it's internal
buffers from overflowing?

(I have seen a 10GbE switch shrink the IFG from 12 to 5 bytes not even
at 100%BW but
I realise that it is a whole different mechanism.)

btw - thanks for the input..
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Rich Seifert
Guest





Posted: Sat Jun 18, 2005 12:20 am    Post subject: Re: IFG at 1000Mb/s Reply with quote

In article <1118971512.601604.16940@g14g2000cwa.googlegroups.com>,
adrian.uliana@gmail.com wrote:

Quote:
By strip, I meant shrink.

So, if you had a switch that was only transfering traffic between 2
ports at 100% BW,
wouldn't almost every IFG by 12 but at some point it'd have to shrink
it to 11 to account
for the clock differences on the 2 ports to prevent it's internal
buffers from overflowing?


Interestingly, in 1000BASE-T, the two devices at the ends of the twisted
pair link use the *same* clock. One is a master, one is a slave; the
slave locks frequency to the master. This is necessary because each
device must know the absolute phase relationship between its own signals
and those of the other device in order to normalize out its own signals,
and crosstalk among the pairs. In the most common configuration, the
central device (switch or router) will be the master for all of its
ports, and all of the devices connected to the switch will be in common
frequency lock. As a result, there will not be any "bit-slippage" due to
clock frequency differences in this configuration.

Unfortunately, this is a special case. It is possible to have one (or
more) of the devices attached to the switch port be the master. In
addition, there may be switch-to-switch connections, and both switches
cannot be the master for all of their ports. Also, there is no
frequency-lock between link partners in 1000BASE-X (fiber). Ultimately a
switch will experience "bit-slippage".

Let's assume (as in your hypothetical) that there is sustained, 100%
offered load between a pair of ports whose clocks are not exactly
identical. (And by definition, two independent oscillators will never be
at the *exact* same frequency.) The worst-case tolerance of the clock is
+/- 100 ppm, or 0.01%. The switch will have some amount of frame
buffering; gigabit switches tend to have lots of buffer (for performance
reasons), but let's say the switch allocates 16KB (about 10 maximum
frame lengths) per port.

Given two devices with worst-case clock tolerances (one is 100 ppm fast,
the other 100 ppm slow), there will be a 0.02% difference. Assume that
the fast device is the one sending, the slow device is receiving. (If
it's the other way around, there is no problem.)

The bit-slippage over a single maximum-length frame will be ~2.4 bits.
If the traffic is sustained, we will overflow the 16KB buffers after
~54,000 frames, or in ~650 ms (at 1000 Mb/s). At that point, unless it
takes some other action, the switch will overflow the buffer and drop a
frame. This will allow some of the buffer to empty out, and the switch
can go back to forwarding that traffic load.

Question: How can the switch tell (absent some special test equipment)
that the buffer overflow was due to clock speed differences? Buffer
overflow can occur for a lot of reasons; the most common is multiple
traffic streams converging to a single output port. The switch can't
measure the clock tolerance; if it could, that implies it has a handy
timing reference that is a whole lot better than +/- 100 ppm!

Answer: It can't. It drops the frame, the same as for any buffer
overflow condition. It does NOT "shrink the IFG," in part because it
doesn't realize that this is the source of the problem, and in part
because the standard doesn't allow it to--a sending station must enforce
the 96 bit IFG; it cannot use a shorter time period. Switches are
stations; they have a MAC entity for each of their ports. They must obey
the IFG requirements.

In practice, this problem does not arise. First, it is highly unlikely
to see sustained, continuous traffic flow at full wire speed for a
period long enough to create this effect. Moreover, the data transfer
would have to be between a pair of devices with worst-case (or
near-worst-case) clock offsets, and the sending station would have to be
the "fast" one.

Even if this situation arose, the fact that the switch dropped an
occasional frame (1 in 54,000, in the example above) would invoke
end-to-end flow control. The loss of a frame will (ultimately) result in
a lack of an acknowledgment for that data. TCP (or some other reliable
transport) would reduce its offered load in response to the missing ACK;
it presumes that data was discarded due to congestion (which is correct,
sort of) and slows down to prevent further loss.

This is exactly what the switch needs; by slowing down, we are no longer
in the "continuous stream data" configuration, and the buffers don't
overflow. That is, dropping a frame is the "right" thing to do. This is
a *control loop*, and dropping a frame provides the feedback to keep the
loop stable. How many of us thought, when we studied control theory as
an undergraduate, that this stuff was applicable to computer networks as
well as radar and servomotors? It's the exact same math, the same
problems, and (for the most part) the same classes of solutions.
Stability, convergence, over/underdamping, oscillatory modes--all of
these things arise in the context of communications protocols.


--
Rich Seifert Networks and Communications Consulting
21885 Bear Creek Way
(408) 395-5700 Los Gatos, CA 95033
(408) 228-0803 FAX

Send replies to: usenet at richseifert dot com
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glen herrmannsfeldt
Guest





Posted: Sat Jun 18, 2005 8:20 am    Post subject: Re: IFG at 1000Mb/s Reply with quote

Rich Seifert wrote:
(snip)

Quote:
Let's assume (as in your hypothetical) that there is sustained, 100%
offered load between a pair of ports whose clocks are not exactly
identical. (And by definition, two independent oscillators will never be
at the *exact* same frequency.) The worst-case tolerance of the clock is
+/- 100 ppm, or 0.01%. The switch will have some amount of frame
buffering; gigabit switches tend to have lots of buffer (for performance
reasons), but let's say the switch allocates 16KB (about 10 maximum
frame lengths) per port.

In many cases it takes very little feedback to phase lock two oscillators.

The old story is of Huygens putting pendulum clocks on the same wall
and having them lock.

The TTL 74S124 dual VCO, it is supposedly impossible to run the two
at different frequencies as they will lock anyway.

LASER gyroscopes using beams in opposite directions through fiber
optics will lock, and miss counts, due to a very small number of
impurities in the fiber.

Women living in the same house will phase lock their menstrual cycle.

Many more examples that I didn't think of.

The question, then, is whether two oscillators really
are independent.

-- glen
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James Knott
Guest





Posted: Sat Jun 18, 2005 4:07 pm    Post subject: Re: IFG at 1000Mb/s Reply with quote

glen herrmannsfeldt wrote:

Quote:
Let's assume (as in your hypothetical) that there is sustained, 100%
offered load between a pair of ports whose clocks are not exactly
identical. (And by definition, two independent oscillators will never be
at the exact same frequency.) The worst-case tolerance of the clock is
+/- 100 ppm, or 0.01%. The switch will have some amount of frame
buffering; gigabit switches tend to have lots of buffer (for performance
reasons), but let's say the switch allocates 16KB (about 10 maximum
frame lengths) per port.

In many cases it takes very little feedback to phase lock two oscillators.


If they're phase locked, they're not independent.
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Rich Seifert
Guest





Posted: Sat Jun 18, 2005 4:20 pm    Post subject: Re: IFG at 1000Mb/s Reply with quote

In article <cvWdnVzf1M-pKS7fRVn-uw@comcast.com>,
glen herrmannsfeldt <gah@ugcs.caltech.edu> wrote:

Quote:

The question, then, is whether two oscillators really
are independent.


As far as the OP's hypothetical is concerned, the question is whether
you can guarantee that the two oscillators are *not* independent. If
they lock, so much the better; the problem doesn't arise. If they don't,
you have to know what to do when the problem does arise.


--
Rich Seifert Networks and Communications Consulting
21885 Bear Creek Way
(408) 395-5700 Los Gatos, CA 95033
(408) 228-0803 FAX

Send replies to: usenet at richseifert dot com
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